On 2008-03-06, Larry <noone@home.com> wrote:
> Dennis Ferguson <dcferguson@pacbell.net> wrote in
> news:slrnfsua9v.4g.dcferguson@akit-ferguson.com:
>
>> it seems like they've also been turning up the output power on the CDMA
>> towers in really remote areas to make up for that. 3W CDMA is guaranteed
>> to be better than 3W AMPS.
>>
>
> No it's not over long distances. FM will work for 100 miles if conditions
> are right. No digital signal, no matter what it's modulation scheme looks
> like, including CDMA, will make a long trip without timing errors and
> multipath reflections causing it to crash. It's just not gonna happen, no
> more than a 20 watt wifi running high speed to a big tower at the tv
> station.
That's silly. I think you probably have personal experience with
CDMA
receivers receiving signals over distances and 12,000 or 16,000 miles from
50 Watt transmitters moving fast enough and far enough from the planet's
gravity field that the receivers have to make corrections for relativistic
time dilation effects, since that is what is in a GPS unit (and I'm trying
not to mention the digital signals they're apparently still getting from
Voyager I, which is out of the solar system and probably 10 billion, with
a 'b', miles away by now). The only difference between the
CDMA in your
GPS receiver and the
CDMA in your cell phone is that the information rate
for the cell phone is a couple of hundred times higher.
The comparison between
CDMA and FM (or anything and anything) is all basic
math. In both cases you have transmitter power, transmit antenna gain,
path loss and a receiver antenna gain, and since RF is RF in both cases
the only modulation-dependent question becomes, do you have enough signal
power at the receive antenna terminals, compared to the noise, to usefully
demodulate that particular kind of signal? For cell phone
CDMA you
require a 6 dB S/N (or, more accurately, Eb/N0) ratio to be useful, for FM
you need 12 dB (according to the ARRL) or 16 dB (according to Qualcomm, may
be self-serving) to have anything worth listening to. If everything else is
equal the
CDMA signal will have a 6-10 dB advantage, which is enough to
win every time.
> A good example of what happens is to simply put a new digital ATSC TV set
> in your car and start driving towards the TV tower transmitting the signal.
So you are picking digital HDTV service, which packs way more information
than analog TV (just compare the pictures when you aren't moving) into
less RF bandwidth, and saying that since the digital receivers don't
(yet?) do as well with certain signal impairments that the digital stuff
is crap? Information rate matters, and the comparison you are making isn't
in the ball park of apples-to-apples. If you want a comparison which is
closer to apples-to-apples why not try, say,
CDMA and FM phones, whose
information rate must be close since they do about the same thing with
about the same quality.
> Turning up the cell site power isn't the problem in the country. The phone
> starts out with a 150 milliwatt transmitter into an almost non-existant
> antenna. The ERP, effective radiated power, is LESS than .15 watts...MAX!
> I don't care what kind of hype you put on it, 150mw on ANY system isn't
> going to go far in the finest conditions. Put it in a pine forest on 800
> or 1900 Mhz and IT WON'T MAKE IT OUT OF THE TREE ATTENUATORS and digital
> sales gimmicks and dreaming won't overcome basic RF physics and
> propagation. A toyphone will NEVER give service over a couple of miles in
> the treed countryside.
Attenuation in the trees is the same for both
CDMA and FM at the same
frequency, the only question in either case is how much signal, and how
little noise, you need left over at the antenna terminal, for it to
do something useful. Some modulations need more signal, some can get by
with less.
CDMA can get by with less while FM needs more, so
CDMA wins.
As for cell site power, note that cell phone transmissions are
bidirectional and the transmission paths are (almost) reciprocal,
so the necessary power in each direction is about the same. The reason
a 3W analog phone is useful is because the tower is willing to spend
3W talking back to the phone. A 3W
CDMA phone won't be useful, however,
if the tower thinks it will only be talking to 200 mW handsets and
won't adjust its own transmit power above that. For higher-power
phones to be useful for anything you need higher-power towers.
I linked to a picture of a 2W
CDMA phone; they exist. For that to be
useful you need cell sites willing to spend 2W to talk back to the phone,
so you need to crank up the power at the tower transmitters. When you've
done that, however, you'll have a system which, given the same antennas
and same RF path, will do better if you spend your 2W on
CDMA than
it will if you spend your 2W on FM. That's all the physics says
about the modulation-dependent part of this.
Dennis Ferguson